Monday, December 7, 2009

Problem Z ZÅ‚apaniem Oddechu How Would I Use A Z-score To Solve This Problem?

How would I use a z-score to solve this problem? - problem z złapaniem oddechu

A company puts its chips in 12.0 ounces of potato chips bags. It's hard to believe that the bag contains enough potato chips to weigh 12.0 ounces and to file a formal complaint. Before you do this, opts for a test run, so you have some confidence that the representation of society is wrong is to have. In the coming months to buy up to 30 bags of potato chips and weigh the contents of the individual. They learn that the average weight of 11.9 kilograms with a standard deviation of 0.4 ounces. You decide who to complain to if it can be 95%, that the bags do not contain at least 12.0 ounces of potato chips.

1 comments:

blahb31 said...

You can use the assumption that the average weight of all bags of these chips is 12.0 ounces.

If this is the case, then if you are on the average of a sample of 30 bags, the average of the sampling distribution is 12.0.

The population standard deviation SD / sqrt (n). We do not know the population SD, but we have a sample that is large enough that only the use of the sample of 0.4 SD. This means that the standard deviation of the sampling, known as () the standard error 0.4/sqrt (30) = 0073.

Now you can calculate the value of 11.9.

z = (11.9-12.0) / 0.073
= -1.37

As if 95%, that the bags do not contain at least 12.0 ounces, so you can find the space to find the right to -1.37 and 0.95, compared to complain. Computers, the 0.9147 area. Since it is 95%, if not complain about you.

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